収束する数列の極限値のε-N論法のTeXコード
lim表記
\displaystyle\lim_{n\to\infty}a_n=\alpha
ε-N論法による表記
太字、Nのε依存を無視
\displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbf{N},{}^{\forall}n\in\mathbf{N}\ \[n\geq N\Rightarrow|a_n-\alpha|\leq\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbf{N},{}^{\forall}n\in\mathbf{N}\ \[n\geq N\Rightarrow|a_n-\alpha|< \epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbf{N},{}^{\forall}n\in\mathbf{N}\ \[n> N\Rightarrow|a_n-\alpha|\leq\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbf{N},{}^{\forall}n\in\mathbf{N}\ \[n> N\Rightarrow|a_n-\alpha|< \epsilon\]
黒板太字、Nのε依存を無視
\displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbb{N},{}^{\forall}n\in\mathbb{N}\ \[n\geq N\Rightarrow|a_n-\alpha|\leq\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbb{N},{}^{\forall}n\in\mathbb{N}\ \[n\geq N\Rightarrow|a_n-\alpha|< \epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbb{N},{}^{\forall}n\in\mathbb{N}\ \[n> N\Rightarrow|a_n-\alpha|\leq\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ ^{\exists}N \in\mathbb{N},{}^{\forall}n\in\mathbb{N}\ \[n> N\Rightarrow|a_n-\alpha|< \epsilon\]
太字、Nのε依存を強調
\displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbf{N},\ {}^{\forall}n\in\mathbf{N}\ \[n\geq N(\epsilon)\Rightarrow|a_n-\alpha|\leq\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbf{N},\ {}^{\forall}n\in\mathbf{N}\ \[n\geq N(\epsilon)\Rightarrow|a_n-\alpha|<\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbf{N},\ {}^{\forall}n\in\mathbf{N}\ \[n> N(\epsilon)\Rightarrow|a_n-\alpha|\leq \epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbf{N},\ {}^{\forall}n\in\mathbf{N}\ \[n> N(\epsilon)\Rightarrow|a_n-\alpha|< \epsilon\]
黒板太字、Nのε依存を強調
\displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbb{N},\ {}^{\forall}n\in\mathbb{N}\ \[n\geq N(\epsilon)\Rightarrow|a_n-\alpha|\leq\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbb{N},\ {}^{\forall}n\in\mathbb{N}\ \[n\geq N(\epsilon)\Rightarrow|a_n-\alpha|<\epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbb{N},\ {}^{\forall}n\in\mathbb{N}\ \[n> N(\epsilon)\Rightarrow|a_n-\alpha|\leq \epsilon\] \displaystyle{}^{\forall}\epsilon>0,\ {}^{\exists}N(\epsilon)\in\mathbb{N},\ {}^{\forall}n\in\mathbb{N}\ \[n> N(\epsilon)\Rightarrow|a_n-\alpha|< \epsilon\]